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Chapters
2: Exponents of Real Numbers
▶ 3: Rationalisation
4: Algebraic Identities
5: Factorisation of Algebraic Expressions
6: Factorisation of Polynomials
7: Linear Equations in Two Variables
8: Co-ordinate Geometry
9: Introduction to Euclid’s Geometry
10: Lines and Angles
11: Triangle and its Angles
12: Congruent Triangles
13: Quadrilaterals
14: Areas of Parallelograms and Triangles
15: Circles
16: Constructions
17: Heron’s Formula
18: Surface Areas and Volume of a Cuboid and Cube
19: Surface Areas and Volume of a Circular Cylinder
20: Surface Areas and Volume of A Right Circular Cone
21: Surface Areas and Volume of a Sphere
22: Tabular Representation of Statistical Data
23: Graphical Representation of Statistical Data
24: Measures of Central Tendency
25: Probability
![RD Sharma solutions for Mathematics [English] Class 9 chapter 3 - Rationalisation RD Sharma solutions for Mathematics [English] Class 9 chapter 3 - Rationalisation - Shaalaa.com](/images/8193647912-mathematics-english-class-9_6:1a030933ece146238cec338f12706a07.jpg)
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Solutions for Chapter 3: Rationalisation
Below listed, you can find solutions for Chapter 3 of CBSE RD Sharma for Mathematics [English] Class 9.
RD Sharma solutions for Mathematics [English] Class 9 3 Rationalisation Exercise 3.1 [Pages 2 - 3]
Simplify of the following:
`root(3)4 xx root(3)16`
Simplify of the following:
`root(4)1250/root(4)2`
Simplify the following expressions:
`(4 + sqrt7)(3 + sqrt2)`
Simplify the following expressions:
`(3 + sqrt3)(5 - sqrt2)`
Simplify the following expressions:
`(sqrt5 - 2)(sqrt3 - sqrt5)`
Simplify the following expressions:
`(11 + sqrt11)(11 - sqrt11)`
Simplify the following expressions:
`(5 + sqrt7)(5 - sqrt7)`
Simplify the following expressions:
`(sqrt8 - sqrt2)(sqrt8 + sqrt2)`
Simplify the following expressions:
`(3 + sqrt3)(3 - sqrt3)`
Simplify the following expression:
`(sqrt5 - sqrt2)(sqrt5 + sqrt2)`
Simplify the following expressions:
`(sqrt3 + sqrt7)^2`
Simplify the following expressions:
`(sqrt5 - sqrt3)^2`
Simplify the following expressions:
`(2sqrt5 + 3sqrt2)^2`
RD Sharma solutions for Mathematics [English] Class 9 3 Rationalisation Exercise 3.2 [Pages 14 - 15]
Rationalise the denominator of each of the following
`3/sqrt5`
Rationalise the denominator of the following:
`3/(2sqrt5)`
Rationalise the denominator of each of the following
`1/sqrt12`
Rationalise the denominator of the following
`sqrt2/sqrt5`
Rationalise the denominator of the following
`(sqrt3 + 1)/sqrt2`
Rationalise the denominator of the following
`(sqrt2 + sqrt5)/3`
Rationalise the denominator of the following
`(3sqrt2)/sqrt5`
Find the value to three places of decimals of the following. It is given that
`sqrt2 = 1.414`, `sqrt3 = 1.732`, `sqrt5 = 2.236` and `sqrt10 = 3.162`
`2/sqrt3`
Find the value to three places of decimals of the following. It is given that
`sqrt2 = 1.414`, `sqrt3 = 1.732`, `sqrt5 = 2.236` and `sqrt10 = 3.162`
`3/sqrt10`
Find the value to three places of decimals of the following. It is given that
`sqrt2 = 1.414`, `sqrt3 = 1.732`, `sqrt5 = 2.236` and `sqrt10 = 3.162`
`(sqrt5 + 1)/sqrt2`
Find the value to three places of decimals of the following. It is given that
`sqrt2 = 1.414`, `sqrt3 = 1.732`, `sqrt5 = 2.236` and `sqrt10 = 3.162`
`(sqrt10 + sqrt15)/sqrt2`
`
Find the value to three places of decimals of the following. It is given that
`sqrt2 = 1.414`, `sqrt3 = 1.732`, `sqrt5 = 2.236` and `sqrt10 = 3.162`
`(2 + sqrt3)/3`
Find the value to three places of decimals of the following. It is given that
`sqrt2 = 1.414`, `sqrt3 = 1.732`, `sqrt5 = 2.236` and `sqrt10 = 3.162`
`(sqrt2 - 1)/sqrt5`
Express the following with rational denominator:
`1/(3 + sqrt2)`
Express of the following with rational denominator:
`1/(sqrt6 - sqrt5)`
Express the following with rational denominator:
`16/(sqrt41 - 5)`
Express the following with rational denominator:
`30/(5sqrt3 - 3sqrt5)`
Express the following with rational denominator:
`1/(2sqrt5 - sqrt3)`
Express the following with rational denominator:
`(sqrt3 + 1)/(2sqrt2 - sqrt3)`
Express the following with rational denominator:
`(6 - 4sqrt2)/(6 + 4sqrt2)`
Express the following with rational denominator:
`(3sqrt2 + 1)/(2sqrt5 - 3)`
Express each one of the following with rational denominator:
`(b^2)/(sqrt(a^2 + b^2) + a)`
Rationales the denominator and simplify:
`(3 - sqrt2)/(3 + sqrt2)`
Rationales the denominator and simplify:
`(5 + 2sqrt3)/(7 + 4sqrt3)`
Rationales the denominator and simplify:
`(1 + sqrt2)/(3 - 2sqrt2)`
Rationales the denominator and simplify:
`(2sqrt6 - sqrt5)/(3sqrt5 - 2sqrt6)`
Rationales the denominator and simplify:
`(4sqrt3 + 5sqrt2)/(sqrt48 + sqrt18)`
Rationales the denominator and simplify:
`(2sqrt3 - sqrt5)/(2sqrt2 + 3sqrt3)`
Simplify:
`(5 + sqrt3)/(5 - sqrt3) + (5 - sqrt3)/(5 + sqrt3)`
Simplify
`1/(2 + sqrt3) + 2/(sqrt5 - sqrt3) + 1/(2 - sqrt5)`
Simplify:
`2/(sqrt5 + sqrt3) + 1/(sqrt3 + sqrt2) - 3/(sqrt5 + sqrt2)`
In the following determine rational numbers a and b:
`(sqrt3 - 1)/(sqrt3 + 1) = a - bsqrt3`
In the following determine rational numbers a and b:
`(4 + sqrt2)/(2 + sqrt2) = n - sqrtb`
In the following determine rational numbers a and b:
`(3 + sqrt2)/(3 - sqrt2) = a + bsqrt2`
In the following determine rational numbers a and b:
`(5 + 3sqrt3)/(7 + 4sqrt3) = a + bsqrt3`
In the following determine rational numbers a and b:
`(sqrt11 - sqrt7)/(sqrt11 + sqrt7) = a - bsqrt77`
In the following determine rational numbers a and b:
`(4 + 3sqrt5)/(4 - 3sqrt5) = a + bsqrt5`
Find the value of `6/(sqrt5 - sqrt3)` it being given that `sqrt3 = 1.732` and `sqrt5 = 2.236`
Find the values the following correct to three places of decimals, it being given that `sqrt2 = 1.4142`, `sqrt3 = 1.732`, `sqrt5 = 2.2360`, `sqrt6 = 2.4495` and `sqrt10 = 3.162`
`(3 - sqrt5)/(3 + 2sqrt5)`
Find the values the following correct to three places of decimals, it being given that `sqrt2 = 1.4142`, `sqrt3 = 1.732`, `sqrt5 = 2.2360`, `sqrt6 = 2.4495` and `sqrt10 = 3.162`
`(1 + sqrt2)/(3 - 2sqrt2)`
Simplify: \[\frac{3\sqrt{2} - 2\sqrt{3}}{3\sqrt{2} + 2\sqrt{3}} + \frac{\sqrt{12}}{\sqrt{3} - \sqrt{2}}\]
Simplify: \[\frac{7 + 3\sqrt{5}}{3 + \sqrt{5}} - \frac{7 - 3\sqrt{5}}{3 - \sqrt{5}}\]
if `x = 2 + sqrt3`,find the value of `x^2 + 1/x^2`
if `x= 3 + sqrt8`, find the value of `x^2 + 1/x^2`
if `x = (sqrt3 + 1)/2` find the value of `4x^2 +2x^2 - 8x + 7`
RD Sharma solutions for Mathematics [English] Class 9 3 Rationalisation Exercise 3.3 [Page 16]
Write the value of \[\left( 2 + \sqrt{3} \right) \left( 2 - \sqrt{3} \right) .\]
Write the reciprocal of \[5 + \sqrt{2}\].
Write the rationalisation factor of \[7 - 3\sqrt{5}\].
If\[\frac{\sqrt{3} - 1}{\sqrt{3} + 1} = x + y\sqrt{3},\] find the values of x and y.
If x= \[\sqrt{2} - 1\], then write the value of \[\frac{1}{x} . \]
If \[a = \sqrt{2} + 1\],then find the value of \[a - \frac{1}{a}\].
If \[x = 2 + \sqrt{3}\] , find the value of \[x + \frac{1}{x}\].
Write the rationalisation factor of \[\sqrt{5} - 2\].
Simplify \[\sqrt{3 + 2\sqrt{2}}\].
Simplify \[\sqrt{3 - 2\sqrt{2}}\].
If \[x = 3 + 2\sqrt{2}\],then find the value of \[\sqrt{x} - \frac{1}{\sqrt{x}}\].
RD Sharma solutions for Mathematics [English] Class 9 3 Rationalisation Exercise 3.4 [Pages 16 - 18]
\[\sqrt{10} \times \sqrt{15}\] is equal to
5\[\sqrt{6}\]
6\[\sqrt{5}\]
\[\sqrt{30}\]
\[\sqrt{25}\]
\[\sqrt[5]{6} \times \sqrt[5]{6}\] is equal to
\[\sqrt[5]{36}\]
\[\sqrt[5]{6 \times 0}\]
\[\sqrt[5]{6}\]
\[\sqrt[5]{12}\]
The rationalisation factor of \[\sqrt{3}\] is
\[- \sqrt{3}\]
\[\frac{1}{\sqrt{3}}\]
\[2\sqrt{3}\]
\[- 2\sqrt{3}\]
The rationalisation factor of \[2 + \sqrt{3}\] is
\[2 - \sqrt{3}\]
\[2 + \sqrt{3}\]
\[\sqrt{2} - 3\]
\[\sqrt{3} - 2\]
If x = \[\sqrt{5} + 2\],then \[x - \frac{1}{x}\] equals
\[2\sqrt{5}\]
4
2
\[\sqrt{5}\]
If \[\frac{\sqrt{3 - 1}}{\sqrt{3} + 1}\] =\[a - b\sqrt{3}\] then
a = 2, b =1
a = 2, b =−1
a = −2, b = 1
a = b = 1
The simplest rationalising factor of \[\sqrt[3]{500}\] is
\[\sqrt[3]{2}\]
\[\sqrt[3]{5}\]
\[\sqrt{3}\]
none of these
The simplest rationalising factor of \[\sqrt{3} + \sqrt{5}\] is ______.
`sqrt3 - 5`
`3 - sqrt5`
`sqrt3 - sqrt5`
`sqrt3 + sqrt5`
The simplest rationalising factor of \[2\sqrt{5}-\]\[\sqrt{3}\] is
\[2\sqrt{5} + 3\]
\[2\sqrt{5} + \sqrt{3}\]
\[\sqrt{5} + \sqrt{3}\]
\[\sqrt{5} - \sqrt{3}\]
If x = \[\frac{2}{3 + \sqrt{7}}\],then (x−3)2 =
1
3
6
7
If \[x = 7 + 4\sqrt{3}\] and xy =1, then \[\frac{1}{x^2} + \frac{1}{y^2} =\]
64
134
194
1/49
If \[x + \sqrt{15} = 4,\] then \[x + \frac{1}{x}\] =
2
4
8
1
If \[x = \frac{\sqrt{5} + \sqrt{3}}{\sqrt{5} - \sqrt{3}}\] and \[y = \frac{\sqrt{5} - \sqrt{3}}{\sqrt{5} + \sqrt{3}}\] then x + y +xy=
9
5
17
7
If x= \[\frac{\sqrt{3} - \sqrt{2}}{\sqrt{3} + \sqrt{2}}\] and y = \[\frac{\sqrt{3} + \sqrt{2}}{\sqrt{3} - \sqrt{2}}\] , then x2 + y +y2 =
101
99
98
102
\[\frac{1}{\sqrt{9} - \sqrt{8}}\] is equal to
\[3 + 2\sqrt{2}\]
\[\frac{1}{3 + 2\sqrt{2}}\]
\[3 - 2\sqrt{2}\]
\[\frac{3}{2} - \sqrt{2}\]
The value of \[\frac{\sqrt{48} + \sqrt{32}}{\sqrt{27} + \sqrt{18}}\] is
\[\frac{4}{3}\]
4
3
`3/4`
If \[\frac{5 - \sqrt{3}}{2 + \sqrt{3}} = x + y\sqrt{3}\] , then
x = 13, y = −7
x = −13, y = 7
x = −13, y =- 7
x = 13, y = 7
If x = \[\sqrt[3]{2 + \sqrt{3}}\] , then \[x^3 + \frac{1}{x^3} =\]
2
4
8
9
The value of \[\sqrt{3 - 2\sqrt{2}}\] is
\[\sqrt{2} - 1\]
\[\sqrt{2} + 1\]
\[\sqrt{3} - \sqrt{2}\]
\[\sqrt{3} + \sqrt{2}\]
The value of \[\sqrt{5 + 2\sqrt{6}}\] is
\[\sqrt{3} - \sqrt{2}\]
\[\sqrt{3} + \sqrt{2}\]
\[\sqrt{5} + \sqrt{6}\]
none of these
If \[\sqrt{2} = 1 . 4142\] then \[\sqrt{\frac{\sqrt{2} - 1}{\sqrt{2} + 1}}\] is equal to
0.1718
5.8282
0.4142
2.4142
If \[\sqrt{2} = 1 . 414,\] then the value of \[\sqrt{6} - \sqrt{3}\] upto three places of decimal is
0.235
0.707
1.414
0.471
The positive square root of \[7 + \sqrt{48}\] is
\[7 + 2\sqrt{3}\]
\[7 + \sqrt{3}\]
\[ \sqrt{3}+2\]
\[3 + \sqrt{2}\]
If \[x = \sqrt{6} + \sqrt{5}\],then \[x^2 + \frac{1}{x^2} - 2 =\]
\[2\sqrt{6}\]
\[2\sqrt{5}\]
24
20
If \[\sqrt{13 - a\sqrt{10}} = \sqrt{8} + \sqrt{5}, \text { then a } =\]
−5
−6
−4
−2
Solutions for 3: Rationalisation
![RD Sharma solutions for Mathematics [English] Class 9 chapter 3 - Rationalisation RD Sharma solutions for Mathematics [English] Class 9 chapter 3 - Rationalisation - Shaalaa.com](/images/8193647912-mathematics-english-class-9_6:1a030933ece146238cec338f12706a07.jpg)
RD Sharma solutions for Mathematics [English] Class 9 chapter 3 - Rationalisation
Shaalaa.com has the CBSE Mathematics Mathematics [English] Class 9 CBSE solutions in a manner that help students grasp basic concepts better and faster. The detailed, step-by-step solutions will help you understand the concepts better and clarify any confusion. RD Sharma solutions for Mathematics Mathematics [English] Class 9 CBSE 3 (Rationalisation) include all questions with answers and detailed explanations. This will clear students' doubts about questions and improve their application skills while preparing for board exams.
Further, we at Shaalaa.com provide such solutions so students can prepare for written exams. RD Sharma textbook solutions can be a core help for self-study and provide excellent self-help guidance for students.
Concepts covered in Mathematics [English] Class 9 chapter 3 Rationalisation are Introduction of Real Number, Concept of Irrational Numbers, Real Numbers and Their Decimal Expansions, Representing Real Numbers on the Number Line, Operations on Real Numbers, Laws of Exponents for Real Numbers.
Using RD Sharma Mathematics [English] Class 9 solutions Rationalisation exercise by students is an easy way to prepare for the exams, as they involve solutions arranged chapter-wise and also page-wise. The questions involved in RD Sharma Solutions are essential questions that can be asked in the final exam. Maximum CBSE Mathematics [English] Class 9 students prefer RD Sharma Textbook Solutions to score more in exams.
Get the free view of Chapter 3, Rationalisation Mathematics [English] Class 9 additional questions for Mathematics Mathematics [English] Class 9 CBSE, and you can use Shaalaa.com to keep it handy for your exam preparation.