Advertisements
Advertisements
Question
Rationales the denominator and simplify:
`(2sqrt3 - sqrt5)/(2sqrt2 + 3sqrt3)`
Solution
We know that rationalization factor for `2sqrt2 + 3sqrt3` is `2sqrt2 - 3sqrt3`. We will multiply numerator and denominator of the given expression `(2sqrt3 - sqrt5)/(2sqrt3 + 3sqrt3)` by `2sqrt2 - 3sqrt3` to get
`(2sqrt3 - sqrt5)/(2sqrt2 + 3sqrt3) xx (2sqrt2 - 3sqrt3)/(2sqrt2 - 3sqrt3) = (2 xx 2 xx sqrt3 xx sqrt2 - 2 xx 3 xx sqrt3 xx sqrt3 - 2 xx sqrt5 xx sqrt2 + 3 xx sqrt5 xx sqrt3)/((2sqrt2)^2 - (3sqrt3)^2)`
`= (4sqrt(3 xx 2) - 6 xx (sqrt3)^2 - 2 xx sqrt(5 xx 2) + 3 xx sqrt(5 xx 3))/(4 xx 2 - 9 xx 3)`
`= (4sqrt6 - 6 xx 3 - 2sqrt10 + 3 sqrt15)/(8 - 27)`
`= (4sqrt6 - 18 - 2sqrt10 + 3sqrt15)/(-19)`
`= (18 + 2sqrt10 - 3sqrt15 - 4sqrt6)/19`
Hence the given expression is simplified to `(18 + 2sqrt10 - 3sqrt15 - 4sqrt6)/19`
APPEARS IN
RELATED QUESTIONS
Simplify the following expression:
`(3+sqrt3)(2+sqrt2)`
Rationalise the denominator of the following
`sqrt2/sqrt5`
Rationalise the denominator of the following
`(sqrt2 + sqrt5)/3`
Express the following with rational denominator:
`16/(sqrt41 - 5)`
Express each one of the following with rational denominator:
`(b^2)/(sqrt(a^2 + b^2) + a)`
Find the value of `6/(sqrt5 - sqrt3)` it being given that `sqrt3 = 1.732` and `sqrt5 = 2.236`
The rationalisation factor of \[\sqrt{3}\] is
Classify the following number as rational or irrational:
2π
Simplify the following:
`4sqrt(28) ÷ 3sqrt(7) ÷ root(3)(7)`
Simplify:
`[((625)^(-1/2))^((-1)/4)]^2`