Advertisements
Advertisements
Question
Rationalise the denominator of each of the following
`3/sqrt5`
Solution
We know that rationalization factor for `1/sqrta` is `sqrta` We will multiply numerator and denominator of the given expression `3/sqrt5` by `sqrt5`to get
`3/sqrt5 xx sqrt5/sqrt5 = (3sqrt5)/(sqrt5 xx sqrt5)`
`= (3sqrt5)/5`
Hence the given expression is simplified to `(3sqrt5)/5`
APPEARS IN
RELATED QUESTIONS
Express the following with rational denominator:
`1/(2sqrt5 - sqrt3)`
Simplify:
`(5 + sqrt3)/(5 - sqrt3) + (5 - sqrt3)/(5 + sqrt3)`
In the following determine rational numbers a and b:
`(3 + sqrt2)/(3 - sqrt2) = a + bsqrt2`
Find the values the following correct to three places of decimals, it being given that `sqrt2 = 1.4142`, `sqrt3 = 1.732`, `sqrt5 = 2.2360`, `sqrt6 = 2.4495` and `sqrt10 = 3.162`
`(1 + sqrt2)/(3 - 2sqrt2)`
Simplify `(3sqrt2 - 2sqrt3)/(3sqrt2 + 2sqrt3) + sqrt12/(sqrt3 - sqrt2)`
The rationalisation factor of \[\sqrt{3}\] is
Rationalise the denominator of the following:
`2/(3sqrt(3)`
Find the value of a and b in the following:
`(5 + 2sqrt(3))/(7 + 4sqrt(3)) = a - 6sqrt(3)`
Rationalise the denominator in the following and hence evaluate by taking `sqrt(2) = 1.414, sqrt(3) = 1.732` and `sqrt(5) = 2.236`, upto three places of decimal.
`6/sqrt(6)`
Simplify:
`64^(-1/3)[64^(1/3) - 64^(2/3)]`