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Find the value to three places of decimals of the following. It is given that 2=1.414, 3=1.732, 5=2.236 and 10=3.162 310 - Mathematics

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Question

Find the value to three places of decimals of the following. It is given that

`sqrt2 = 1.414`, `sqrt3 = 1.732`, `sqrt5 = 2.236` and `sqrt10 = 3.162`

`3/sqrt10`

Sum

Solution

 We know that rationalization factor of the denominator is `sqrt10`. We will multiply numberator and denominator of the given expression `3/sqrt10` by `sqrt10to get

`3/sqrt10 xx sqrt10/sqrt10 = (3 xx sqrt10)/(sqrt10 xx sqrt10)`

`= (3sqrt10)/10`

`= (3 xx 3.162)/10`

`= 9.486/10`

= 0.9486

The value of expression 0.9486 can be round off to three decimal places as 0.949.

Hence the given expression is simplified to 0.949.

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Chapter 3: Rationalisation - Exercise 3.2 [Page 14]

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RD Sharma Mathematics [English] Class 9
Chapter 3 Rationalisation
Exercise 3.2 | Q 2.2 | Page 14

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