Advertisements
Advertisements
Question
The simplest rationalising factor of \[\sqrt[3]{500}\] is
Options
\[\sqrt[3]{2}\]
\[\sqrt[3]{5}\]
\[\sqrt{3}\]
none of these
Solution
Given that: `3sqrt500` To find simplest rationalizing factor of the given expression we will factorize it as
`3sqrt500 = 3sqrt(125xx 4)`
`= 3sqrt(5xx5xx5xx 4)`
`= 3sqrt((5))^3 xx 3sqrt4`
` = 5 3sqrt4`
The rationalizing factor of `5 3sqrt4`is, `3sqrt2`since when we multiply given expression with this factor we get rid of irrational term.
Therefore, rationalizing factor of the given expression is `3sqrt2`
APPEARS IN
RELATED QUESTIONS
Simplify:-
`2^(2/3). 2^(1/5)`
If a = 3 and b = -2, find the values of :
aa + bb
Prove that:
`sqrt(3xx5^-3)divroot3(3^-1)sqrt5xxroot6(3xx5^6)=3/5`
Prove that:
`((0.6)^0-(0.1)^-1)/((3/8)^-1(3/2)^3+((-1)/3)^-1)=(-3)/2`
Show that:
`(x^(a^2+b^2)/x^(ab))^(a+b)(x^(b^2+c^2)/x^(bc))^(b+c)(x^(c^2+a^2)/x^(ac))^(a+c)=x^(2(a^3+b^3+c^3))`
Find the value of x in the following:
`2^(5x)div2x=root5(2^20)`
Find the value of x in the following:
`(3/5)^x(5/3)^(2x)=125/27`
Solve the following equation:
`4^(2x)=(root3 16)^(-6/y)=(sqrt8)^2`
If a, m, n are positive ingegers, then \[\left\{ \sqrt[m]{\sqrt[n]{a}} \right\}^{mn}\] is equal to
If \[\sqrt{2} = 1 . 414,\] then the value of \[\sqrt{6} - \sqrt{3}\] upto three places of decimal is