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Rationalise the denominator in the following and hence evaluate by taking 2=1.414,3=1.732 and 5=2.236, upto three places of decimal. 22+2 - Mathematics

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Question

Rationalise the denominator in the following and hence evaluate by taking `sqrt(2) = 1.414, sqrt(3) = 1.732` and `sqrt(5) = 2.236`, upto three places of decimal.

`sqrt(2)/(2 + sqrt(2)`

Sum

Solution

Let `E = sqrt(2)/(2 + sqrt(2)`

For rationalising the denominator, multiplying numerator and denominator by `2 - sqrt(2)`, we get

= `sqrt(2)/(2 + sqrt(2)) xx (2 - sqrt(2))/(2 - sqrt(2))`

= `(sqrt(2)(2 - sqrt(2)))/((2)^2 - (sqrt(2))^2`  ...[Using identity, (a – b)(a + b) = a2 – b2]

= `(sqrt(2) xx sqrt(2)(sqrt(2) - 1))/2`

= `(2(sqrt(2) - 1))/2`

= `sqrt(2) - 1`  ...[Put `sqrt(2)` = 1.414]

= 1.414 – 1

= 0.414  

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Chapter 1: Number Systems - Exercise 1.3 [Page 11]

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NCERT Exemplar Mathematics [English] Class 9
Chapter 1 Number Systems
Exercise 1.3 | Q 13. (iv) | Page 11

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