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Rationalise the denominator in the following and hence evaluate by taking 2=1.414,3=1.732 and 5=2.236, upto three places of decimal. 10-52 - Mathematics

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Question

Rationalise the denominator in the following and hence evaluate by taking `sqrt(2) = 1.414, sqrt(3) = 1.732` and `sqrt(5) = 2.236`, upto three places of decimal.

`(sqrt(10) - sqrt(5))/2`

Sum

Solution

Let `E = (sqrt(10) - sqrt(5))/2`

= `(sqrt(5) sqrt(2) - sqrt(5))/2`

= `(sqrt(5)(sqrt(2) - 1))/2`  ...`[∵ sqrt(10) = sqrt(2) sqrt(5)]`

= `(2.236(1.414 - 1))/2`

= 1.118 × 0.414

= 0.46285 ≅ 0.463

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Chapter 1: Number Systems - Exercise 1.3 [Page 11]

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NCERT Exemplar Mathematics [English] Class 9
Chapter 1 Number Systems
Exercise 1.3 | Q 13. (iii) | Page 11

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