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Question
In the following, find the co-ordinates of the point whose abscissa is the solution of the first equation and ordinate is the solution of the second equation:
`5x - (5 - x) = (1)/(2) (3 - x); 4 -3y = (4 + y)/(3)`
Solution
`5x - (5 - x) = (1)/(2) (3 - x); 4 -3y = (4 + y)/(3)`
Now
`5x - (5 - x) = (1)/(2)(3 - x)`
`(5x + x) -5 = (1)/(2)(3 - x)`
12 x - 10 = 3 - x
12x + x = 3 +10
13x = 13
x = 1
Again
4 - 3y = `(4 + y)/(3)`
12 - 9y = 4 + y
12 - 4 = y + 9y
8 = 10y
`(8)/(10)` = y
`(4)/(5)`= y
∴ The co-ordinates of the point `(1,4/5)`
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