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Question
In Figure 1, PS = 3 cm, QS = 4 cm, ∠PRQ = θ, ∠PSQ = 90°, PQ ⊥ RQ and RQ = 9 cm. Evaluate tan θ.
Solution
Given,
PS = 3 cm, QS = 4 cm, RQ = 9cm
In In ΔPSQ,
PQ2 =PS2 + OS2
PQ2 = 32 +42 = 25
⇒ PQ = 5 cm
In Δ PQR,
tan θ =`"PQ"/"RQ"`
⇒ tan θ =`5/9`
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