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Question
In a game of chance, a spinning arrow comes to rest at one of the numbers 1, 2, 3, 4, 5, 6, 7, 8. All these are equally likely outcomes. Find the probability that it will rest at an odd number.
Solution
Total number of outcomes = 8
Number of favourable outcomes (odd number) = 1, 3, 5, 7
= 4
Therefore, required probability =`\text {Number of favorable outcomes}/text { Total number of outcomes}`
`=4/8`
`=1/2`
Hence, the probability that the spinning arrow will rest at odd number is `=1/2`.
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