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In the figure, given below, PQR is a right-angle triangle right angled at Q. XY is parallel to QR, PQ = 6 cm, PY = 4 cm and PX : XQ = 1 : 2. Calculate the lengths of PR and QR. - Mathematics

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Question

In the figure, given below, PQR is a right-angle triangle right angled at Q. XY is parallel to QR, PQ = 6 cm, PY = 4 cm and PX : XQ = 1 : 2. Calculate the lengths of PR and QR.

Sum

Solution

Given that `(PX)/(XQ) = 1/2` and XY || QR

So, `(PX)/(XQ) = (PY)/(YR) = 1/2`

Since PY = 4 cm, YR = 8 cm.

Hence, PR = 12 cm

Since ΔPQR is a right-angled triangle

By Pythagoras theorem,

QR2 = PR2 – PQ2

`=>` QR2 = 122 – 62

`=>` QR2 = 144 – 36

`=>` QR2 = 108

`=>` QR = 10.39 cm

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Chapter 15: Similarity (With Applications to Maps and Models) - Exercise 15 (B) [Page 218]

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Selina Mathematics [English] Class 10 ICSE
Chapter 15 Similarity (With Applications to Maps and Models)
Exercise 15 (B) | Q 8 | Page 218
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