Question

In the given figure ∠BAP = ∠DCP = 70°, PC = 6 cm and CA = 4 cm, then PD : DB is ______.

Options

• 5 : 3

• 3 : 5

• 3 : 2

• 2 : 3

Answer 1

In the given figure ∠BAP = ∠DCP = 70°, PC = 6 cm and CA = 4 cm, then PD : DB is 3 : 2.

Explanation:

In ΔAPB and ΔCPD,

∠A = ∠C = 70°   ...(Given)

And ∠P = ∠P    ...(Common)

∴ ΔAPB ∼ ΔCPD   ...(By AA – axiom)

So, `(PD)/(DB) = (PC)/(CA) = 6/4 = 3/2`

∴ PD : DB = 3 : 2