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Question
In the given figure, the value of a is ______.
Options
20°
15°
5°
10°
Solution
In the given figure, the value of a is 10°.
Explanation:
We have,
∠AOF = ∠COD ......[Vertically opposite angles]
∴ ∠COD = 90°
Now, 40° + 90° + 5a = 180° .....[Angles on a straight line BOE]
⇒ 5a + 130° = 180°
⇒ 5a = 180° – 130° = 50°
⇒ a = `50^circ/5` = 10°
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