English
Karnataka Board PUCPUC Science Class 11

Locate the Image of the Point P as Seen by the Eye in the Figure. - Physics

Advertisements
Advertisements

Question

Locate the image of the point P as seen by the eye in the figure.

Sum

Solution

Given,
From the figure we can infer that the air is present in between the sheet, so it does not affect the shift. Therefore, the shift is only due to 3 sheets of different refractive indices, which is given by:
\[∆ t = \left[ 1 - \frac{1}{\mu_1} \right] t_1  + \left[ 1 - \frac{1}{\mu_2} \right] t_2  + \left[ 1 - \frac{1}{\mu_3} \right] t_3\]
\[= \left[ 1 - \left( \frac{1}{12} \right) \right]\left( 0 . 2 \right) + \left[ 1 - \left( \frac{1}{1 . 3} \right) \right]\left( 0 . 3 \right) + \left[ 1 - \left( \frac{1}{1 . 4} \right) \right]\left( 0 . 4 \right)\]
= 0.2 cm
Hence, location of image of point P is located 0.2 cm above point P.

shaalaa.com
  Is there an error in this question or solution?
Chapter 18: Geometrical Optics - Exercise [Page 413]

APPEARS IN

HC Verma Concepts of Physics Vol. 1 [English] Class 11 and 12
Chapter 18 Geometrical Optics
Exercise | Q 19 | Page 413

RELATED QUESTIONS

Why does unpolarised light from a source show a variation in intensity when viewed through a polaroid which is rotated?


Show with the help of a diagram, how unpolarised light from Sun gets linearly polarised by scattering.


Draw the intensity distribution for the fringes produced in interference ?


Draw the intensity distribution for the diffraction bands produced due to single slit ?


 Write two points of difference between the phenomena of interference and diffraction.


What is linearly polarized light? 


A parallel beam of light is incident on a converging lens parallel to its principal axis. As one moves away from the lens on the other side on its principal axis, the intensity of light


A point object O is placed on the principal axis of a convex lens of focal length f = 20 cm at a distance of 40 cm to the left of it. The diameter of the lens is 10 cm. An eye is placed 60 cm to right of the lens and a distance h below the principal axis. The maximum value of h to see the image is


A candle flame 1.6 cm high is imaged in a ball bearing of diameter 0.4 cm. If the ball bearing is 20 cm away from the flame, find the location and the height of the image.


A 3 cm tall object is placed at a distance of 7.5 cm from a convex mirror of focal length 6 cm. Find the location, size and nature of the image.


Fill in the blank and rewrite the completed statement:

Very fine particles mainly scatter ______ light.


Answer the following question in detail.

Explain the formation of a primary rainbow. For which angular range with the horizontal is it visible?


Pick the wrong answer in the context with rainbow.


State any one difference between a primary rainbow and a secondary rainbow.


Explain the formation of primary and secondary rainbow.


A parallel beam of light of wavelength 5890 Å falls normally on a slit of width 0.2 mm. Find the distance between the first minima on the two sides of the central maximum of the diffraction pattern observed on a screen placed in the focal plane of a convex lens of focal length 50 cm. The lens is placed quite close to the slit.


Case study: Mirage in deserts

To a distant observer, the light appears to be coming from somewhere below the ground. The observer naturally assumes that light is being reflected from the ground, say, by a pool of water near the tall object.

Such inverted images of distant tall objects cause an optical illusion to the observer. This phenomenon is called mirage. This type of mirage is especially common in hot deserts.

Based on the above facts, answer the following question :

In an optical fibre, if n1 and n2 are the refractive indices of the core and cladding, then which among the following, would be a correct equation? 


A short pulse of white light is incident from air to a glass slab at normal incidence. After travelling through the slab, the first colour to emerge is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×