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Question
Match the structures of compounds given in Column I with the classes of compounds given in Column II.
Column I | Column II | |
(i) | \[\begin{array}{cc} \ce{CH3 - CH - CH3}\\ |\phantom{..}\\ \ce{X}\phantom{..} \end{array}\] |
(a) Aryl halide |
(ii) | \[\ce{CH2 = CH - CH2 - X}\] | (b) Alkyl halide |
(iii) | ![]() |
(c) Vinyl halide |
(iv) | \[\ce{CH2 = CH - X}\] | (d) Allyl halide |
Solution
Column I | Column II | |
(i) | \[\begin{array}{cc} \ce{CH3 - CH - CH3}\\ |\phantom{..}\\ \ce{X}\phantom{..} \end{array}\] |
(b) Alkyl halide |
(ii) | \[\ce{CH2 = CH - CH2 - X}\] | (d) Allyl halide |
(iii) | ![]() |
(a) Aryl halide |
(iv) | \[\ce{CH2 = CH - X}\] | (c) Vinyl halide |
Explanation:
(i) In alkyl halide, the halogen atom is bonded to sp3 hybridised carbon atom, which may be further bonded to one, two or three alkyl groups, i.e., \[\begin{array}{cc}
\ce{CH3 - CH - CH3}\\
|\phantom{..}\\
\ce{X}\phantom{..}
\end{array}\]
(ii) Allyl halides are the compounds in which the halogen atom is bonded to sp3 hybridised carbon atom next to the carbon-carbon double bond, i.e., \[\ce{CH2 = CH - CH2 - X}\]
(iii) Aryl halides are the compounds in which the halogen atom is bonded to the sp2 hybridised carbon atom of an aromatic ring, i.e., \[\ce{C6H5X}\]
(iv) Vinyl halides are the compounds in which the halogen atom is bonded to an sp2 hybridised carbon atom of a carbon-carbon double bond, i.e., \[\ce{CH2 = CH-X}\]
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