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Multiply the following: (3x2 + 4x – 8), (2x2 – 4x + 3) - Mathematics

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Question

Multiply the following:

(3x2 + 4x – 8), (2x2 – 4x + 3)

Sum

Solution

We have,

(3x2 + 4x – 8) and (2x2 – 4x + 3)

∴ (3x2 + 4x – 8)(2x2 – 4x + 3) = 3x2(2x2 – 4x + 3) + 4x(2x2 – 4x + 3) – 8(2x2 – 4x + 3)

= 6x4 – 12x3 + 9x2 + 8x3 – 16x2 + 12x – 16x2 + 32x – 24

= 6x4 – 12x3 + 8x3 + 9x2 – 16x2 – 16x2 + 12x + 32x – 24  ...[Grouping like terms]

= 6x4 – 4x3 – 23x2 + 44x – 24

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Chapter 7: Algebraic Expression, Identities and Factorisation - Exercise [Page 231]

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NCERT Exemplar Mathematics [English] Class 8
Chapter 7 Algebraic Expression, Identities and Factorisation
Exercise | Q 83. (xxi) | Page 231

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