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प्रश्न
Multiply the following:
(3x2 + 4x – 8), (2x2 – 4x + 3)
उत्तर
We have,
(3x2 + 4x – 8) and (2x2 – 4x + 3)
∴ (3x2 + 4x – 8)(2x2 – 4x + 3) = 3x2(2x2 – 4x + 3) + 4x(2x2 – 4x + 3) – 8(2x2 – 4x + 3)
= 6x4 – 12x3 + 9x2 + 8x3 – 16x2 + 12x – 16x2 + 32x – 24
= 6x4 – 12x3 + 8x3 + 9x2 – 16x2 – 16x2 + 12x + 32x – 24 ...[Grouping like terms]
= 6x4 – 4x3 – 23x2 + 44x – 24
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