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Question
O(0, 0), A(3, 5) and B(−5, −3) are the vertices of triangle OAB. Find the equation of altitude of triangle OAB through vertex B.
Solution
The altitude through vertex B is perpendicular to OA.
Slope of OA = `(5 - 0)/( 3 - 0) = 5/3`
Slope of the required altitude = `(-1)/(5/3)= (-3)/5`
The equation of the required altitude through B is
y – y1 = m(x – x1)
`y + 3 = (-3)/5 (x + 5)`
5y + 15 = −3x − 15
3x + 5y + 30 = 0
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