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Question
One mole of PCl5 is heated in one litre closed container. If 0.6 mole of chlorine is found at equilibrium, Calculate the value of equilibrium constant.
Solution
Given that,
`["PCl"_5]_"initial" = (1 "mole")/(1 "dm"^3)`
[Cl2]eq = 0.6 mole dm-3
\[\ce{PCl5 <=> PCL3 + Cl2}\]
[PCl3]eq = 0.6 mole dm-3
[PCl5]eq = 0.4 mole dm-3
`therefore "K"_"C" = (["PCl"_3]["Cl"_2])/(["PCl"_5])`
`= (0.6 xx 0.6)/0.4`
= 0.9 mole dm-3
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