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Question
\[\ce{[CO(H2O)6]^2+ (aq) (pink) + 4Cl- (aq) <=> [CoCl4]^2- (aq) (blue) + 6 H2O (l)}\]
In the above reaction at equilibrium, the reaction mixture is blue in colour at room temperature. On cooling this mixture, it becomes pink in color. On the basis of this information, which one of the following is true?
Options
∆H > 0 for the forward reaction
∆H = 0 for the reverse reaction
∆H < 0 for the forward reaction
Sign of the ∆H cannot be predicted based on this information
Solution
∆H > 0 for the forward reaction
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