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Question
What is the relation between Kp and Kc? Given one example for which Kp is equal to Kc.
Solution
The relation between Kp and Kc is Kp =
KC (RT)∆ng
Kp = equilibrium constant is terms of partial pressure.
Kc = equilibrium constant is terms of concentration.
R = gas constant
T = Temperature.
∆ng = Difference between the sum of the number of moles of products and the sum of a number of moles of reactants in the gas phase.
When ∆ng = 0
Kp = KC(RT)0 = KC i.e., Kp = KC
Example: \[\ce{H2(g) + l2(g) <=> 2HI(g)}\]
∆ng = 2 – 2 = 0
∴ Kp = KC for the synthesis of HI.
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