Advertisements
Advertisements
Question
Present age of father is 42 years and that of his son is 14 years. Find the ratio of age of father after 10 years to the age of son after 10 years.
Solution
After ten years father's age = 42 + 10 = 52 years
After ten years son's age = 14 + 10 = 24 years
Required ratio = `52/24 = (4 xx 13)/(4 xx 6) = 13/6`
APPEARS IN
RELATED QUESTIONS
If A : B = 2 : 5 and A : C = 3 : 4, find: A : B : C.
If a: b = 4: 7, find the following:
`(5"a" - 4"b")/(2"a" - 3"b")`
If a : e = 5 : 12, e : i = 8 : 3 and i : u = 9 : 16, then find a : u
The ages of two boys A and B are 6 years 8 months and 7 years 4 months respectively. Divide Rs. 3,150 in the ratio of their ages.
Check whether the following quantities form a proportion or not?
`2 1/2, 5 1/2, 3.0 "and" 6.0`
Find the duplicate ratio of 2 : 3
If a : b = 9 : 10, find the value of `(2a^2 - 3b^2)/(2a^2 + 3b^2)`
Ratio of 5 km 400 m to 6 km = _______________
A rectangular sheet of paper is of length 1.2 m and width 21 cm. Find the ratio of width of the paper to its length.
Given below is a Mathematical term.
Find the ratio of consonants to vowels in the term.
