Question

Show the formation of Na2O by the transfer of electrons. 

Answer 1

${\displaystyle N{a}_{2}O}$

Na=11=2,8,1 (Valency = 1)

O = 8 = 2,6  (Valency = 2)

(a) ${\displaystyle Na\to N{a}^{+}+e^{-}}$

      ${\displaystyle (Na\to N{a}^{+}+e^{-})\times 2}$

      ${\displaystyle 2Na\to 2Na+2e^{-}}$

(b) ${\displaystyle O+e^{-}\to O^{-}}$

      ${\displaystyle (O+e^{-}\to O^{-})\times 2}$

       ${\displaystyle 2O+2e^{-}\to O^{-}}$

${\displaystyle i.e.2Na+O\to N{a}_{2}O}$