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Maharashtra State BoardSSC (English Medium) 8th Standard

Simplify. (2a + b)3 − (2a − b)3 - Marathi (Second Language) [मराठी (द्वितीय भाषा)]

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Question

Simplify.

(2a + b)− (2a − b)3

Simplify

Solution

We know that,

(a + b)3 = a3 + 3a2b + 3ab2 + b3

(a − b)3 = a3 − 3a2b + 3ab2 − b3

(2a + b)− (2a − b)3

= [(2a)3 + 3(2a)2(b) + 3(2a)(b)2 + (b)3] − [(2a)3 − 3(2a)2(b) + 3(2a)(b)2 − (b)3]

= 8a3 + 3(4a2)(b) + 3(2a)(b2) + b3 − 8a3 + 3(4a2)(b) − 3(2a)(b2) + b3

= 8a3 − 8a3 + 12a2b + 12a2b + 6ab2 − 6ab2 + b3 + b3

= 12a2b + b3 + 12a2b + b3

= 24a2b + 2b3

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Chapter 5: Expansion formulae - Practice Set 5.3 [Page 27]

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Balbharati Mathematics [English] 8 Standard Maharashtra State Board
Chapter 5 Expansion formulae
Practice Set 5.3 | Q 2.1 | Page 27
Balbharati Integrated 8 Standard Part 1 [English Medium] Maharashtra State Board
Chapter 3.5 Expansion formulae
Practice Set 5.3 | Q 2. (1) | Page 66
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