English

Simplify : 5^( N + 3 ) - 6 Xx 5^( N + 1 )/9 Xx 5^N - 5^N Xx 2^2 - Mathematics

Advertisements
Advertisements

Question

Simplify :
`[ 5^( n + 3 ) - 6 xx 5^( n + 1 )]/[ 9 xx 5^n - 5^n xx 2^2 ]`

Sum

Solution

`[ 5^( n + 3 ) - 6 xx 5^( n + 1 )]/[ 9 xx 5^n - 5^n xx 2^2 ]`

= `[ 5^( n + 1 ) xx 5^2- 6 xx 5^( n + 1 )]/[ 9 xx 5^n - 5^n xx 2^2 ]`

= `[ 5^( n + 1 ) xx ( 5^2 - 6 )]/[ 5^n xx ( 9 - 4 )]`

= `[ 5^1 xx 19 ]/5`

= 19

shaalaa.com
Laws of Exponents
  Is there an error in this question or solution?
Chapter 7: Indices (Exponents) - Exercise 7 (A) [Page 98]

APPEARS IN

Selina Concise Mathematics [English] Class 9 ICSE
Chapter 7 Indices (Exponents)
Exercise 7 (A) | Q 2.3 | Page 98
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×