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Question
`[(3/7)^-3]^4` = ______
Options
`(3/7)^-7`
`(3/7)^-10`
`(7/3)^12`
`(3/7)^20`
Solution
`[(3/7)^-3]^4 = bbunderline((7/3)^12)`
Explanation:
`[(3/7)^-3]^4 = (3/7)^(-3(4))` ...[∵ (am)n = amn]
`= (3/7)^-12`
`= (7/3)^12` ....`[∵ (a)^-"n" = 1/"a"^"n"]`
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