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Question
Six men can complete a work in 12 days. Two days later, 6 more men joined them. How many days will they take to complete the remaining work?
Solution
| Number of men | No. of days | |
| Initially | 6 | 12 |
| 2 days later available work | 6 | 12 − 2 = 10 |
| Remaining work after 6 men joined | 6 + 6 = 12 | x |
As the number of men increases the number of days decreases.
∴ They are inversely proportional
x1y1 = x2y2
6 × 10 = 12 × x
x = `(6 xx 10)/12`
x = 5 days
∴ Remaining work will be complete in 5 days
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