Advertisements
Advertisements
Question
Solve: `|(2,x,3),(4,1,6),(1,2,7)|` = 0
Solution
`|(2,x,3),(4,1,6),(1,2,7)|` = 0
`2 |(1,6),(2,7)| - x|(4,6),(1,7)| + 3|(4,1),(1,2)|` = 0
2(7 – 12) – x(28 – 6) + 3(8 – 1) = 0
2(-5) – x(22) + 3(7) = 0
- 10 – 22x + 21 = 0
- 22x + 11 = 0
- 22x = - 11
x = `(-11)/(-22) = 1/2`
APPEARS IN
RELATED QUESTIONS
Find the minors and cofactors of all the elements of the following determinant.
`|(5,20),(0, -1)|`
Find the minors and cofactors of all the elements of the following determinant.
`|(1,-3,2),(4,-1,2),(3,5,2)|`
The value of the determinant `[(a,0,0),(0,b,0),(0,0,c)]^2` is
Evaluate the following determinants:
`|(a,h,g), (h,b,f), (g,f,c)|`
Evaluate the following determinants:
`|(4,7),(-7,0)|`
Evaluate the following determinant:
`|(3,-5,2),(1,8,9),(3,7,0)|`
Evaluate the following determinant:
`|(3,-5,2),(1,8,9),(3,7,0)|`
Without expanding evaluate the following determinant.
`|(1,a,b+c),(1,b,c+a),(1,c, a+b)|`
Evaluate the following determinant:
`|("a","h","g"),("h","b","f"),("g","f","c")|`
Evaluate the following determinant:
`|(3, -5, 2),(1, 8, 9),(3, 7, 0)|`
