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प्रश्न
Solve: `|(2,x,3),(4,1,6),(1,2,7)|` = 0
उत्तर
`|(2,x,3),(4,1,6),(1,2,7)|` = 0
`2 |(1,6),(2,7)| - x|(4,6),(1,7)| + 3|(4,1),(1,2)|` = 0
2(7 – 12) – x(28 – 6) + 3(8 – 1) = 0
2(-5) – x(22) + 3(7) = 0
- 10 – 22x + 21 = 0
- 22x + 11 = 0
- 22x = - 11
x = `(-11)/(-22) = 1/2`
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