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Question
Solve: `("d"y)/("d"x) = y sin 2x`
Solution
`("d"y)/("d"x) = y sin 2x`
⇒ `("d"y)/y = sin 2x "d"x`
Integrating on both sides
`int 1/y "d"y = int sin 2x "d"x`
⇒ log y = `(- cos 2x)/2 + "c"`
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