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Question
Solve the equation by using the formula method. 3y2 +7y + 4 = 0
Solution
The given quadratic equation is 3y2 + 7y + 4 = 0.
Comparing the given equation with ax2 + bx + c = 0 we get,
a = 3, b = 7 and c = 4
`y=(-b+-sqrt(b^2-4ac))/(2a)`
`y=(-7+-sqrt(7^2-4ac))/(2(3))`
`y=(-7+-sqrt(49-48))/6`
`y=(-7+-sqrt(1))/6`
`y=(-7+-1)/(6)`
`y=(-7+1)/(6) or y=(-7-1)/(6)`
`y=-6/6=-1 or y=-8/6=-4/3`
`y=-1 or y=-4/3`
Therefore `-1` and `-4/3` are the roots of given equation.
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