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Question
Solve the following equation: 3x2 + 25 x + 42 = 0
Solution
3x2 + 25 x + 42 = 0
`"x"^2 + 25/3 "x" + 14 = 0`
`"x"^2 + 6"x" + 7/3 "x" + 14 = 0`
`"x"("x" + 6) + 7/3 ("x" + 6) = 0`
`("x" + 6)("x" + 7/3) = 0`
(x + 6) = 0 , `("x" + 7/3) = 0`
x = -6 , x = `-7/3`
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