English

Solve the Following Pairs of Equations by Reducing Them to a Pair of Linear Equations - Mathematics

Advertisements
Advertisements

Question

Solve the following pairs of equations by reducing them to a pair of linear equations

`2/sqrtx +3/sqrty = 2`

`4/sqrtx - 9/sqrty = -1`

Solution

`2/sqrtx +3/sqrty = 2`

`4/sqrtx - 9/sqrty = -1`

Let `1/sqrtx = p ` , then the equations changes as below:

2p + 3q = 2 ... (i)

4p - 9q = -1 ... (ii)

Multiplying equation (i) by 3, we get

6p + 9q = 6 ... (iii)

Adding equation (ii) and (iii), we get

10p = 5

p = 1/2 ... (iv)

Putting in equation (i), we get

`2 × 1/2 + 3q = 2`

3q = 1

`q = 1/3`

`p = 1/sqrtx = 1/2`

`sqrtx = 2`

x = 4 and q = `1/sqrty = 1/3`

`sqrty = 3`

y = 9

Hence, x = 4, y = 9

shaalaa.com
  Is there an error in this question or solution?
Chapter 3: Pair of Linear Equations in Two Variables - Exercise 3.6 [Page 67]

APPEARS IN

NCERT Mathematics [English] Class 10
Chapter 3 Pair of Linear Equations in Two Variables
Exercise 3.6 | Q 1.2 | Page 67

RELATED QUESTIONS

Solve the following pairs of equations by reducing them to a pair of linear equations

`1/(2x) + 1/(3y) = 2`

`1/(3x) + 1/(2y) = 13/6`


Solve the following pairs of equations by reducing them to a pair of linear equations

`10/(x+y) + 2/(x-y) = 4`

`15/(x+y) - 5/(x-y) = -2`


Solve the following pairs of equations by reducing them to a pair of linear equations

`1/(3x+y) + 1/(3x-y) = 3/4`

`1/(2(3x-y)) - 1/(2(3x-y)) = (-1)/8`


One says, "Give me a hundred, friend! I shall then become twice as rich as you". The other replies, “If you give me ten, I shall be six times as rich as you”. Tell me what is the amount of their (respective) capital? [From the Bijaganita of Bhaskara II)

[Hint: x + 100 = 2 (y − 100), y + 10 = 6(x − 10)]


Solve the following pair of linear equations: px + qy = p − q, qx − py = p + q


Solve the following pair of linear equations

ax + by = c

bx + ay = 1 + c


Solve the following pair of linear equations.

(a − b) x + (a + b) y = a2− 2ab − b2

(a + b) (x + y) = a2 + b2


The sum of a two digit number and the number obtained by reversing the order of its digits is 99. If the digits differ by 3, find the number.


A two-digit number is 4 times the sum of its digits and twice the product of the digits. Find the number.


The numerator of a fraction is 4 less than the denominator. If the numerator is decreased by 2 and denominator is increased by 1, then the denominator is eight times the numerator. Find the fraction.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×