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Question
Solve problem:
Calculate the mass of sulfur dioxide produced by burning 16 g of sulfur in excess of oxygen in the contact process. (Average atomic mass : S = 32 u, O = 16 u)
Solution
Given: Mass of sulfur (reactant) = 16 g
To find: Mass of sulfur dioxide (product)
Calculation: 32 g of sulfur combine with 32 g oxygen to form 64 g of sulfur dioxide as follows:
\[\ce{\underset{\text{32 g}}{sulfur} + \underset{\text{32 g}}{Oxygen}->\underset{\text{64 g}}{sulfur dioxide}}\]
Hence, (0.5 × 32 = 16 g) of sulfur will combine with (0.5 × 32 = 16 g) of oxygen to give (0.5 × 64 = 32 g) sulfur dioxide.
Mass of sulfur dioxide produced = 32 g
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