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Question
Solve the given inequality for real x : `x/3 > x/2 + 1`
Solution
The given inequality `x/3 > x/2 + 1`
`x/3 - x/2 > 1`
or `(2x - 3x)/6 > 1`
= `-x/6 > 1`
-On multiplying by 6,
x < - 6
Thus, all real numbers x, which are less than -6, are the solutions of the given inequality.
Hence, the solution set of the given inequality is (–∞, –6).
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