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Question
Split 207 into three parts such that these parts are in A.P. and the product of the two smaller parts in 4623.
Solution
Let the three parts in A.P. be (a – d), a and (a + d)
Then, (a – d) + a + (a + d) = 207
`\implies` 3a = 207
`\implies` a = `207/3` = 69
It is given that
(a – d) × a = 4623
`\implies` (69 – d) × 69 = 4623
`\implies` 69 – d = `4623/69` = 67
`\implies` d = 69 – 67 = 2
`\implies` a = 69 and d = 2
Thus, we have
a – d = 69 – 2 = 67
a = 69
a + d = 69 + 2 = 71
Thus, the three parts in A.P. are 67, 69 and 71.
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