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Split 207 into three parts such that these parts are in A.P. and the product of the two smaller parts in 4623. - Mathematics

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Question

Split 207 into three parts such that these parts are in A.P. and the product of the two smaller parts in 4623.

Sum

Solution

Let the three parts in A.P. be (a – d), a and (a + d)

Then, (a – d) + a + (a + d) = 207 

`\implies` 3a = 207

`\implies` a = `207/3` = 69

It is given that 

(a – d) × a = 4623

`\implies` (69 – d) × 69 = 4623

`\implies` 69 – d = `4623/69` = 67

`\implies` d = 69 – 67 = 2

`\implies` a = 69 and d = 2

Thus, we have 

a – d = 69 – 2 = 67

a = 69

a + d = 69 + 2 = 71

Thus, the three parts in A.P. are 67, 69 and 71.

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Simple Applications of Arithmetic Progression
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Chapter 10: Arithmetic Progression - Exercise 10 (D) [Page 146]

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Selina Mathematics [English] Class 10 ICSE
Chapter 10 Arithmetic Progression
Exercise 10 (D) | Q 6 | Page 146
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