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Standing Waves of Frequency 5.0 Khz Are Produced in a Tube Filled with Oxygen at 300 K. the Separation Between the Consecutive Nodes is 3.3 Cm. - Physics

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Question

Standing waves of frequency 5.0 kHz are produced in a tube filled with oxygen at 300 K. The separation between the consecutive nodes is 3.3 cm. Calculate the specific heat capacities Cp and Cv of the gas.

Answer in Brief

Solution

Frequency of standing waves, f = 5 × 103 Hz
Temperature of oxygen, T = 300 K
From Kundt's tube theory, we know that`"l" / 2` = node separation = 3.3 cm
∴ l = 6.6 × 10−2 m
Also,
v = fl = 5 × 103 × 6.6 × 10−2
= (66 × 5) = 330 m/s

`"v" = sqrt((gamma "R""T")/"M")`

`"v"^2=(gamma "R""T")/"M"`

`therefore  gamma = (330 xx 330 xx 32)/(8.3 xx 300 xx 100 ) = 1.3995`

Specific heat at constant volume , `"C"_"v" = "R"/(gamma -1) = 8.3/0.3995`

= 20.7 J mol -K

Specific heat at constant pressure, Cp = Cv + R
Cp = 20.7 + 8.3
Cp = 29.0 J/mol-K

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Chapter 5: Specific Heat Capacities of Gases - Exercises [Page 80]

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HC Verma Concepts of Physics Vol. 2 [English] Class 11 and 12
Chapter 5 Specific Heat Capacities of Gases
Exercises | Q 35 | Page 80

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