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Question
Tap A can empty a tank in 6 hours. Tap A along with Tap B together can empty the tank in `3(3)/(7)" hours"`. Find the time Tap B alone will take to empty the tank.
Solution
Time taken bt Tap A to empty the tank = 6 hours
Amount of work done by tap A in 1 hour = `(1)/(6)`
Let B takes x hour to empty the tank alone.
Amount of work done by tap B in 1 hour = `(1)/x`
∴ Amount of work done by (A + b) in 1 hour = `(1)/x + (1)/(6)`
Tap A along with Tap B together can empty the tank in `3(3)/(7)" hours" = (24)/(7)" hours"`
∴ In 1 hour amount of work done by A and B = `(1)/((24)/(7)) = (7)/(24)`
Now, according to the question
`(1)/x + (1)/(6) = (7)/(24)`
⇒ `(1)/x = (7)/(24) - (1)/(6)`
= `(7 - 4)/(24)`
= `(3)/(24)`
= `(1)/(8)`
⇒ x = 8hrs.
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