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Question
The circumference of a circle is 22 cm. Find the area of its quadrant.
Solution
Let the radius of the circle be r.
Now,
Circumference = 22
⇒ 2πr = 22
`⇒ r = (22xx7)/44 = 7/2 "cm"`
Now, Area of quadrant `=1/4pi"r"^2=1/4xx22/7xx(7/2)^2=77/8 "cm"^2`
Hence, the area of the quadrant of the circle is `77/8 "cm"^2`.
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