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Question
The cross section of a swimming pool is a trapezium whose shallow and deep ends are 1 m and 3 m respectively. If the length of the pool is 50 m and its width is 1.5 m, calculate the volume of water it holds.
Solution
Area of cross-section
= Area of trapezium
= `(1)/(2) xx ("sum of parallel sides") xx "height"`
= `(1)/(2) xx (1 + 3) xx 1.5`
= 3m2
Volume of the pool
= Area of cross-section x length
= 3 x 50
= 150m3
∴ The volume of the pool is 150m3.
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