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Question
A rectangular field is 112 m long and 62 m broad. A cubical tank of edge 6 m is dug at each of the four corners of the field and the earth so removed is evenly spread on the remaining field. Find the rise in level.
Solution
Vol. of the tank= vol. of earth spread
4 x 63 m3 = ( 112 x 62 - 4 x 62 ) m2 x Rise in level
Rise in level = `( 4 xx 6^3)/ ( 112 xx 62 - 4 xx 6^2)`
= `( 864) / ( 6800)`
= 0.127 m
= 12.7 cm
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