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Question
The figure represents the cross section of a swimming pool 10 m broad, 2 m deep at one end, 3 m deep at the other end. Calculate the volume of water it will hold when full, given that its length is 40 m.
Solution
The given figure is a trapezium because 2 opposite sides are parallel.
length of the pool = 40m
height of the trapezium = 10m
Area of cross section = Area of trapezium
= `(1)/(2) xx ("sum of parallel sides") xx "height"`
= `(1)/(2) xx (2 + 3) xx 10`
= 25m2
Volume of the pool = Area of cross section x length
= 25 x 40
= 1000m3
∴ The volume of the pool is 1000m3
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