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The curved surface area of a frustum of a cone is πl (r1 + r2), where l=h2+(r1+r2)2, r1 and r2 are the radii of the two ends of the frustum and h is the vertical height. - Mathematics

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Question

The curved surface area of a frustum of a cone is πl (r1 + r2), where `l = sqrt(h^2 + (r_1 + r_2)^2)`, r1 and r2 are the radii of the two ends of the frustum and h is the vertical height.

Options

  • True

  • False

MCQ
True or False

Solution

This statement is False.

Explanation:

We know that,

Curved surface area of frustum = πl(r1 + r2)

Where r1 and r2 are the radii of two ends (r1 > r2)

And l = slant height

`l = sqrt(h^2 + (r_1 + r_2)^2)`   ...[In the statement, formula for calculating slant height is incorrect]

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Chapter 12: Surface Areas and Volumes - Exercise 12.2 [Page 143]

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NCERT Exemplar Mathematics [English] Class 10
Chapter 12 Surface Areas and Volumes
Exercise 12.2 | Q 7 | Page 143

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