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The Diagram Below in Fig. 8.40 Shows a Cell of E.M.F. ε = 2 Volt and Internal Resistance R = 1 Ohm To an External Resistance R = 4 Ohm. the Ammeter a Measures the Current in the Circuit and the - Physics

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Question

The diagram below in Fig. 8.40 shows a cell of e.m.f. ε = 2 volt and internal resistance r = 1 ohm to an external resistance R = 4 ohm. The ammeter A measures the current in the circuit and the
voltmeter V measures the terminal voltage across the cell. What will be the readings of the ammeter and voltmeter when (i) the key K is open, (ii) the key K is closed. 

  

Solution

(i) Ammeter reading = 0 because of no current
Voltage V = ϵ − Ir
V = 2 − 0 × 1 = 2 volt  

(ii) Ammeter reading :
I =ε /(R + r)
I=2 / (4+1) = 2 / 5 = 0.4 amp
Voltage reading :
Voltage V = ϵ - Ir
V=2 - 0.4 x 1 = 2 - 0.4 = 1.6 V

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Internal Resistance of a Cell
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Chapter 8: Current Electricity - Exercise 8 (B) 3 [Page 201]

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Selina Physics [English] Class 10 ICSE
Chapter 8 Current Electricity
Exercise 8 (B) 3 | Q 1 | Page 201

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