Advertisements
Advertisements
Question
The difference of a two-digit number and the number obtained by reversing its digits is always divisible by ______.
Solution
The difference of a two-digit number and the number obtained by reversing its digits is always divisible by 9.
Explanation:
Let ab be any two-digit number, then we have
ab – ba = (10a + b) – (10b + a)
= 9a – 9b
= 9(a – b)
Hence, ab – ba is always divisible by 9 and (a – b).
APPEARS IN
RELATED QUESTIONS
If \[\overline{{3x2}}\] is a multiple of 11, where x is a digit, what is the value of x?
Now you try and change these numbers into special numbers —
28
The sum of a two-digit number and the number obtained by reversing the digits is always divisible by ______.
A four-digit number abcd is divisible by 11, if d + b = ______ or _____.
If A × 3 = 1A, then A = ______.
A three-digit number abc is divisible by 6 if c is an even number and a + b + c is a multiple of 3.
If AB + 7C = 102, where B ≠ 0, C ≠ 0, then A + B + C = 14.
If N ÷ 5 leaves remainder 3 and N ÷ 2 leaves remainder 0, then N ÷ 10 leaves remainder 4.
A five-digit number AABAA is divisible by 33. Write all the numbers of this form.
If 56 × 32y is divisible by 18, find the least value of y.