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Question
The equations of the two lines of regression are 2x + 3y − 6 = 0 and 5x + 7y − 12 = 0. Find the value of the correlation coefficient `("Given" sqrt(0.933) = 0.9667)`
Solution
r = `+- sqrt("b"_(xy) * "b"_(yx))`
= `+- sqrt((-7)/5 xx (-2)/3)`
= `+- sqrt(0.933)`
= 0.9667
Since the values of bXY and bYX are negative,
r is also negative.
∴ r = – 0.9667
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Mean of x = 25
Mean of y = 20
`sigma_x` = 4
`sigma_y` = 3
r = 0.5
byx = `square`
bxy = `square`
when x = 10,
`y - square = square (10 - square)`
∴ y = `square`
x | y | xy | x2 | y2 |
6 | 9 | 54 | 36 | 81 |
2 | 11 | 22 | 4 | 121 |
10 | 5 | 50 | 100 | 25 |
4 | 8 | 32 | 16 | 64 |
8 | 7 | `square` | 64 | 49 |
Total = 30 | Total = 40 | Total = `square` | Total = 220 | Total = `square` |
bxy = `square/square`
byx = `square/square`
∴ Regression equation of x on y is `square`
∴ Regression equation of y on x is `square`
|bxy + byz| ≥ ______.