Question

The intensity of the electric field at a point at a perpendicular distance ‘r’ from an infinite line charge, having linear charge density ‘λ’ is given by:

Options

• E = ${\displaystyle \left(\frac{1}{4\pi {\in }_0}\right)\frac{\lambda }{r}}$

• E = ${\displaystyle \left(\frac{1}{4\pi {\in }_0}\right)\frac{2\lambda }{r}}$

• E = ${\displaystyle \left(\frac{1}{4\pi {\in }_0}\right)\frac{\lambda }{r^2}}$

• E = ${\displaystyle \left(\frac{1}{4\pi {\in }_0}\right)\frac{2\lambda }{r^2}}$

Answer 1

E = ${\displaystyle \left(\frac{1}{4\pi {\in }_0}\right)\frac{2\lambda }{r}}$

The intensity of the electric field at a point at a perpendicular distance ‘r’ from an infinite line charge, having linear charge density ‘λ’ is given by: E = ${\displaystyle \left(\frac{1}{4\pi {\in }_0}\right)\frac{2\lambda }{r}}$