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The oxidizing agent in the equation S+2HA2SOA4⟶3SOA2+2HA2O is ______. - Chemistry

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Question

The oxidizing agent in the equation \[\ce{S + 2H2SO4 -> 3SO2 + 2H2O}\] is ______.

Options

  • Sulphur

  • Sulphuric acid

  • Sulphur dioxide

  • Water

MCQ
Fill in the Blanks

Solution

The oxidizing agent in the equation \[\ce{S + 2H2SO4 -> 3SO2 + 2H2O}\] is sulphuric acid.

Explanation:

The reaction is as follows:

\[\ce{S + 2H2SO4(conc{.}) -> 3SO2 + 2H2O}\]

The oxidizing agent in this process is concentrated \[\ce{H2SO4}\]. While being converted to \[\ce{SO2}\], it oxidizes sulphur \[\ce{(S)}\] to produce sulphur dioxide \[\ce{SO2}\].

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