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Question
The radii of the top and bottom of a bucket of slant height 45 cm are 28 cm and 7 cm, respectively. The curved surface area of the bucket is ______.
Options
4950 cm2
4951 cm2
4952 cm2
4953 cm2
Solution
The radii of the top and bottom of a bucket of slant height 45 cm are 28 cm and 7 cm, respectively. The curved surface area of the bucket is 4950 cm2.
Explanation:
Given, the radius of the top of the bucket, R = 28 cm
And the radius of the bottom of the bucket, r = 7 cm
Slant height of the bucket, l = 45 cm
Since, bucket is in the form of frustum of a cone.
∴ Curved surface area of the bucket = πl (R + r)
= π × 45(28 + 7) ...[∵ Curved surface area of frustum of a cone = π(R + r)l]
= π × 45 × 35
= `22/7 xx 45 xx 35`
= 4950 cm2
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