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Question
The roots of the equation `ax^2+bx+c=0` will be reciprocal each other if
(a)a=b (b)b=c (c)=a (d)= none of these
Solution
(c) c = a
Let the roots of the equation `(ax^2+bx+c) be α and 1/α`
∴ Product of the roots =`αxx1/α=1`
⇒ `c/a=1`
⇒` c=a`
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